log.abit confused?
Friday, December 21st, 20074dimensions? asked:
3log(b2)x=log(b2)8
can i just move the left side to the right like this:
3=[log(b2)8]/[log(b2)x]
so
3=log(b2)[8-x]
then:
2^3=8-x…….but if this way is right then x would be undefined, so i though of another way to do it:
log(b2)(x^3) = log(b2)8
cancle the logs:
x^3=8
x=2
how come this way works? couls some one explain this to me, thanks
oooo i got it so the first part i can use negative?(subtraction?
Roger
3log(b2)x=log(b2)8
can i just move the left side to the right like this:
3=[log(b2)8]/[log(b2)x]
so
3=log(b2)[8-x]
then:
2^3=8-x…….but if this way is right then x would be undefined, so i though of another way to do it:
log(b2)(x^3) = log(b2)8
cancle the logs:
x^3=8
x=2
how come this way works? couls some one explain this to me, thanks
oooo i got it so the first part i can use negative?(subtraction?
Roger
