About Siding

7 Responses to “getting rid of this freakin log?”

1. bustersmycat Says:
   June 28th, 2007 at 7:31 pm

   exponent. 10^0.5=a/b

2. greenwhite Says:
   July 1st, 2007 at 7:53 am

   log (base x) y = z
   x to the power of z = y

   Assuming that is base 10,

   10^0.5 = a/b

3. flickchick99 Says:
   July 3rd, 2007 at 7:55 pm

   yeah, like the person above said

4. j_r_colbert Says:
   July 6th, 2007 at 6:09 pm

   log (a/b)=.5

   Unless a base is given, 10 is assumed

   10^.5=a/b

   Is there more info?

   Are you solving for a or b?

5. Peacock11 Says:
   July 8th, 2007 at 9:54 am

   exponentiate each side by 10
   it would look like:
   10^.5 = 10^log (a/b)
   10^.5 = a/b

6. James Says:
   July 9th, 2007 at 1:14 pm

   log(a/b)=0.5
   a/b=1^0.5
   a/b=1^1/2
   a/b=root(1)
   i.e a/b=1

7. Venkat R Says:
   July 11th, 2007 at 8:43 am

   What is the difficulty ? It is same as saying
   10^(0.5) = a/b
   I think it is better you reverse the order of your expression as log(a/b) = 0.5 .
   Log itself means base10 ( I don’t know how to subscript here 10 between ‘log’ and ‘(a/b)’.