yefimthegreat asked: for this problem:
https://webwork.rutgers.edu/webwork2_files/tmp/equations/cb/dfe49bc5a68e9a9716ee3fc8407a5f1.png
you take the natural log of both sides, and you are left with x+7=x, which leaves 7=0, which is not defined. is that correct?
Christopher
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September 26th, 2007 at 3:51 am
e^(x+7) = e^x + 1. Subtract e^x from both sides.
e^(x+7) - e^x = 1. Factor out e^x.
(e^x)(e^7 - 1) = 1.
e^x = 1/(e^7 - 1).
x = ln (1/(e^7 - 1)).