Help with Natural Log, E?
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kmtiburona asked:
I know I should know this, but been working on it all night and can’t seem to get it.
I know I should know this, but been working on it all night and can’t seem to get it.
5xe^x=0
(5 times x times e to the x power equals 0)
I can’t take the natural log of both sides, and if I divide by 5, it doesn’t seem to get me anywhere either.
Thanks in advance for the help!
Katherine











January 20th, 2008 at 7:35 pm
To start with, you have the statement that 5 times an unknown is zero. The only way that can be true is if the unknown is zero. True?
so e^x=0
taking the natural log (ln) of both sides, you have
x=-infinity
You know the log (in any base) of 1 is 0. The log (in any base, of a fraction less than 1 is negative.
And the closer you get to zero, the more negative is the log.
Not easy to graph, but easy to imagine.