Help with Natural Log, E?

Posted by admin
kmtiburona asked:


I know I should know this, but been working on it all night and can’t seem to get it.

5xe^x=0
(5 times x times e to the x power equals 0)

I can’t take the natural log of both sides, and if I divide by 5, it doesn’t seem to get me anywhere either.

Thanks in advance for the help!

Katherine

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  • One Response to “Help with Natural Log, E?”

    1. jesteele1948 Says:

      To start with, you have the statement that 5 times an unknown is zero. The only way that can be true is if the unknown is zero. True?

      so e^x=0

      taking the natural log (ln) of both sides, you have
      x=-infinity

      You know the log (in any base) of 1 is 0. The log (in any base, of a fraction less than 1 is negative.
      And the closer you get to zero, the more negative is the log.

      Not easy to graph, but easy to imagine.