How do i take the natural log of both sides when the equation is y= (3x+3)^(5x+1)?

Posted by admin
hlnov13 asked:


but the answer has to be
lny = ln(answer)
[this is an online math assignment]

Willie
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    2 Responses to “How do i take the natural log of both sides when the equation is y= (3x+3)^(5x+1)?”

    1. unreliable thinker Says:
      August 15th, 2007 at 10:30 am

      ln y = (5x+1) ln (3x + 3)
      ln stands for log to the base e

    2. lon_usa2003 Says:
      August 16th, 2007 at 8:13 am

      Simple.

      ln y = ln (3x+3) ^ 5x+1
      ln y = bring the exponent down so… (5x+1) ln (3x+3)

      Then, raise everything to the e power so…

      e^ln y = e^ (5x+1) e^ ln (3x+3)

      Now e to the power of ln y just equals y, so…

      y = (3x+3) e ^ (5x+1)

      That’s it. Hoped it helped