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	<title>Comments on: How do i take the natural log of both sides when the equation is y= (3x+3)^(5x+1)?</title>
	<link>http://www.about-siding.com/how-do-i-take-the-natural-log-of-both-sides-when-the-equation-is-y-3x35x1/152/</link>
	<description>Your Questions, Our Answers</description>
	<pubDate>Thu, 09 Feb 2012 03:23:02 +0000</pubDate>
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		<title>By: lon_usa2003</title>
		<link>http://www.about-siding.com/how-do-i-take-the-natural-log-of-both-sides-when-the-equation-is-y-3x35x1/152/#comment-236</link>
		<author>lon_usa2003</author>
		<pubDate>Thu, 16 Aug 2007 12:13:04 +0000</pubDate>
		<guid>http://www.about-siding.com/how-do-i-take-the-natural-log-of-both-sides-when-the-equation-is-y-3x35x1/152/#comment-236</guid>
		<description>Simple.

ln y = ln (3x+3) ^ 5x+1
ln y = bring the exponent down so... (5x+1) ln (3x+3)

Then, raise everything to the e power so...

e^ln y = e^ (5x+1) e^ ln (3x+3)

Now  e to the power of ln y just equals y, so...

y =  (3x+3) e ^ (5x+1)

That's it. Hoped it helped</description>
		<content:encoded><![CDATA[<p>Simple.</p>
<p>ln y = ln (3x+3) ^ 5x+1<br />
ln y = bring the exponent down so&#8230; (5x+1) ln (3x+3)</p>
<p>Then, raise everything to the e power so&#8230;</p>
<p>e^ln y = e^ (5x+1) e^ ln (3x+3)</p>
<p>Now  e to the power of ln y just equals y, so&#8230;</p>
<p>y =  (3x+3) e ^ (5x+1)</p>
<p>That&#8217;s it. Hoped it helped</p>
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		<title>By: unreliable thinker</title>
		<link>http://www.about-siding.com/how-do-i-take-the-natural-log-of-both-sides-when-the-equation-is-y-3x35x1/152/#comment-235</link>
		<author>unreliable thinker</author>
		<pubDate>Wed, 15 Aug 2007 14:30:43 +0000</pubDate>
		<guid>http://www.about-siding.com/how-do-i-take-the-natural-log-of-both-sides-when-the-equation-is-y-3x35x1/152/#comment-235</guid>
		<description>ln y = (5x+1) ln (3x + 3)
ln stands for log to the base e</description>
		<content:encoded><![CDATA[<p>ln y = (5x+1) ln (3x + 3)<br />
ln stands for log to the base e</p>
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