Pelican asked: “By taking log (to the base 10 *or* the base e) of both sides, solve the equation 3^x = 10 for x.”
Rosa
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on Thursday, September 6th, 2007 at 2:29 pm and is filed under siding.
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September 8th, 2007 at 8:28 pm
I choose log to the base e, ln, because it is nicer :).
so, 3^x=10. take logs => ln(3^x)=ln(10) => xln3=ln10 =>
x=ln10/ln3
September 9th, 2007 at 3:58 am
x log 3 = log 10
x = log 10/log 3
x = 1/.477
x = 2.096
September 10th, 2007 at 4:22 am
x log 3 = log 10
x = log 10/log 3
x = 1/.477
x = 2.096
September 13th, 2007 at 5:18 am
3^x = 10
x lg 3 = lg 10
x = lg10/lg3
use calculator
September 15th, 2007 at 2:32 pm
Let logs be logs to base 10 :-
3^x = 10
x log 3 = log 10
x log 3 = 1
x = 1 / log 3
x = 2.096