log ? I must have been out for this whole unit?

Posted by admin
Maggie L asked:


1. find the value of x log x289/169=2

2. evaluate the expression log2 1 (in the text the 2 next to the log is below the word a little and then the 1 is normal next to it, how do i write that or type that should I say)

3. evaluate the expression log6 6^2

4. assume that x,y,and z are possitive #’s. use the properties of logarithms to write the expression log (3sqrtx^2y4/z^3 in terms of logarithms of x,y and z.
a)2/3logx+2/3logy+logz b)2/3logx+4/3logy-logz

5. write the equation (1/3)^-5=243 in logarithmic form

6. find the value of x log2 32=x

7. fill in the blank to make it a true satement .To solve 3^x=30 we can take the logarithm of each side of the equation to get log (3^x)=log (30). the power rule for logarithms would then provide a way of moving the variable x from its position as an ____________ to the positive coefficient.

8. x is a possitive #. use the logarithm property to present the expression log(x+2)-logx as the logarithrm singl

Virginia

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    2 Responses to “log ? I must have been out for this whole unit?”

    1. shah c Says:
      July 11th, 2007 at 11:11 am

      i thnk it’s one of the longest qustions in Y!A!;)
      so i just answer 2 of them!
      1.log x289/169=2 => logx+log289+log169=log100 =>invoice=> x+289+169=100 => x=-358

    2. Kia Says:
      July 14th, 2007 at 4:59 am

      1.
      log x289/169 = 2
      log x + log (289/169) = 2
      log x + log (17^2 / 13^2) = 2
      log x + log (17/13)^2 = 2
      log x + 2 log (17/13) = 2
      log x = 2 - 2 log (17/13)
      log x = 2(1 - log (17/13))
      log x = 2(1 - log (17) + log(13))
      log x = 2(log (10) - log (17) + log(13))
      log x = 2 log (10*13/17)
      log x = 2 log (130/17)
      log x = log (130/17)^2
      x = (130/17)^2
      x = 58.4775

      2.
      log(base 2) 1 = 0

      3.
      log(base 6) 6^2
      = log (6^2) / log 6
      = 2 log 6 / log 6
      = 2

      4. I think instead of 3sqrt you mean cube root
      log (cuberoot(x^2 y^4 / z^3))
      = 1/3 log (x^2 y^4 / z^3)
      = 1/3 (log (x^2) + log (y^4) - log(z^3))
      = 1/3 (2log (x) + 4log (y) - 3log(z))
      = 2/3log (x) + 4/3log (y) - log(z)

      The correct answer is b

      5.
      log (base 1/3) 243 = -5

      6.
      log(base 2) 32
      = log 32 / log 2
      = log 2^5 / log 2
      = 5 log 2 / log 2
      = 5

      7. exponent

      I hope this helped (even though a bit late perhaps)

      Kia