Comments on: log ? I must have been out for this whole unit? http://www.about-siding.com/log-i-must-have-been-out-for-this-whole-unit/178/ Your Questions, Our Answers Mon, 21 May 2012 06:09:30 +0000 http://wordpress.org/?v=2.2.1 By: Kia http://www.about-siding.com/log-i-must-have-been-out-for-this-whole-unit/178/#comment-263 Kia Sat, 14 Jul 2007 08:59:19 +0000 http://www.about-siding.com/log-i-must-have-been-out-for-this-whole-unit/178/#comment-263 1. log x289/169 = 2 log x + log (289/169) = 2 log x + log (17^2 / 13^2) = 2 log x + log (17/13)^2 = 2 log x + 2 log (17/13) = 2 log x = 2 - 2 log (17/13) log x = 2(1 - log (17/13)) log x = 2(1 - log (17) + log(13)) log x = 2(log (10) - log (17) + log(13)) log x = 2 log (10*13/17) log x = 2 log (130/17) log x = log (130/17)^2 x = (130/17)^2 x = 58.4775 2. log(base 2) 1 = 0 3. log(base 6) 6^2 = log (6^2) / log 6 = 2 log 6 / log 6 = 2 4. I think instead of 3sqrt you mean cube root log (cuberoot(x^2 y^4 / z^3)) = 1/3 log (x^2 y^4 / z^3) = 1/3 (log (x^2) + log (y^4) - log(z^3)) = 1/3 (2log (x) + 4log (y) - 3log(z)) = 2/3log (x) + 4/3log (y) - log(z) The correct answer is b 5. log (base 1/3) 243 = -5 6. log(base 2) 32 = log 32 / log 2 = log 2^5 / log 2 = 5 log 2 / log 2 = 5 7. exponent I hope this helped (even though a bit late perhaps) Kia 1.
log x289/169 = 2
log x + log (289/169) = 2
log x + log (17^2 / 13^2) = 2
log x + log (17/13)^2 = 2
log x + 2 log (17/13) = 2
log x = 2 - 2 log (17/13)
log x = 2(1 - log (17/13))
log x = 2(1 - log (17) + log(13))
log x = 2(log (10) - log (17) + log(13))
log x = 2 log (10*13/17)
log x = 2 log (130/17)
log x = log (130/17)^2
x = (130/17)^2
x = 58.4775

2.
log(base 2) 1 = 0

3.
log(base 6) 6^2
= log (6^2) / log 6
= 2 log 6 / log 6
= 2

4. I think instead of 3sqrt you mean cube root
log (cuberoot(x^2 y^4 / z^3))
= 1/3 log (x^2 y^4 / z^3)
= 1/3 (log (x^2) + log (y^4) - log(z^3))
= 1/3 (2log (x) + 4log (y) - 3log(z))
= 2/3log (x) + 4/3log (y) - log(z)

The correct answer is b

5.
log (base 1/3) 243 = -5

6.
log(base 2) 32
= log 32 / log 2
= log 2^5 / log 2
= 5 log 2 / log 2
= 5

7. exponent

I hope this helped (even though a bit late perhaps)

Kia

]]> By: shah c http://www.about-siding.com/log-i-must-have-been-out-for-this-whole-unit/178/#comment-262 shah c Wed, 11 Jul 2007 15:11:07 +0000 http://www.about-siding.com/log-i-must-have-been-out-for-this-whole-unit/178/#comment-262 i thnk it's one of the longest qustions in Y!A!;) so i just answer 2 of them! 1.log x289/169=2 => logx+log289+log169=log100 =>invoice=> x+289+169=100 => x=-358 i thnk it’s one of the longest qustions in Y!A!;)
so i just answer 2 of them!
1.log x289/169=2 => logx+log289+log169=log100 =>invoice=> x+289+169=100 => x=-358

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