Comments on: log.abit confused? http://www.about-siding.com/logabit-confused/186/ Your Questions, Our Answers Mon, 21 May 2012 06:11:37 +0000 http://wordpress.org/?v=2.2.1 By: Alvaro http://www.about-siding.com/logabit-confused/186/#comment-270 Alvaro Wed, 26 Dec 2007 13:00:45 +0000 http://www.about-siding.com/logabit-confused/186/#comment-270 I'll use lg to mean log in base 2. 3lg(x) = lg(8) lg(x^3) = lg(8) x^3 = 8 x = 2 What you did with converting a quotient of logs into the log of the difference doesn't work. It's the other way around: The log of a quotient is the difference of the logs. Also, if 2^3 = 8-x then x is 0, not undefined. I’ll use lg to mean log in base 2.
3lg(x) = lg(8)
lg(x^3) = lg(8)
x^3 = 8
x = 2

What you did with converting a quotient of logs into the log of the difference doesn’t work. It’s the other way around: The log of a quotient is the difference of the logs.

Also, if 2^3 = 8-x then x is 0, not undefined.

]]> By: Pi R Squared http://www.about-siding.com/logabit-confused/186/#comment-269 Pi R Squared Mon, 24 Dec 2007 21:01:16 +0000 http://www.about-siding.com/logabit-confused/186/#comment-269 Hi, 3log(b2)x=log(b2)8 log(b2)x³=log(b2)8 x³ = 8 x = 2 Hi,

3log(b2)x=log(b2)8

log(b2)x³=log(b2)8

x³ = 8

x = 2

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