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	<title>Comments on: Taking the natural log of both sides? V(t) = 100000e^0.095t, t in weeks ? Please help?</title>
	<link>http://www.about-siding.com/taking-the-natural-log-of-both-sides-vt-100000e0095t-t-in-weeks-please-help/150/</link>
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	<pubDate>Mon, 21 May 2012 06:45:29 +0000</pubDate>
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		<title>By: Seri s</title>
		<link>http://www.about-siding.com/taking-the-natural-log-of-both-sides-vt-100000e0095t-t-in-weeks-please-help/150/#comment-234</link>
		<author>Seri s</author>
		<pubDate>Wed, 25 Jul 2007 09:34:58 +0000</pubDate>
		<guid>http://www.about-siding.com/taking-the-natural-log-of-both-sides-vt-100000e0095t-t-in-weeks-please-help/150/#comment-234</guid>
		<description>V(t) = 100000e^0.095t
500000 =100000e^0.095t
500000/100000 =e^0.095t
5=e^0.095t
ln 5 = ln (e^0.095t)
ln 5 = 0.095t*ln (e)
ln 5 = 0.095t*1
ln 5 = 0.095t
(ln 5)/0.095 = t
t=16.9 or 17 

so 17 weeks, it will reach her target viewing.</description>
		<content:encoded><![CDATA[<p>V(t) = 100000e^0.095t<br />
500000 =100000e^0.095t<br />
500000/100000 =e^0.095t<br />
5=e^0.095t<br />
ln 5 = ln (e^0.095t)<br />
ln 5 = 0.095t*ln (e)<br />
ln 5 = 0.095t*1<br />
ln 5 = 0.095t<br />
(ln 5)/0.095 = t<br />
t=16.9 or 17 </p>
<p>so 17 weeks, it will reach her target viewing.</p>
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